Sorry, for creating a separate thread for this discussion.
I did performed a search for ContentHandler and ‘multipart/form-data’ but couldnt find anything which really explains what exactly needs to be done to achieve a fileUpload task in wM65.
I have an HTML form with the enctype=‘multipart/form-data’ and with one of the input field as ‘file’ type.
When I submit the form on this dsp page, the receiving flow service on my IS receives this in the pipeline:VTTest "uploadFile"; filename="C:\Documents and Settings\A17L2ZZ\Desktop\Support\Alloc_QA.txt" Content-Type: text/plain EDI_DOC_ID nvarchar(255) ORTG_LOC_CODE nvarchar(10) NULL
My Questions are:
- does this output indicates that the IS have the right ContentHandler already loaded to parse the form data?
- If yes, how to extract the contents from the selected file? Are there specific I/p signatures for the receive service?
Please advice…your help is much appreciated.