Hi All I am new in webservice .
I have created provide for webservice descripte and consumer also in same IS with existing service that is add 2 number.
when i run the webservice connector its successfully.its give me the correct result with on URL. when I try to open this URL its showing
<?xml version="1.0" encoding="UTF-8" ?>- <SOAP-ENV:Envelope xmlns:SOAP-ENV=“http://schemas.xmlsoap.org/soap/envelope/” xmlns:xsi=“http://www.w3.org/1999/XMLSchema-instance” xmlns:xsd=“http://www.w3.org/1999/XMLSchema”>
- SOAP-ENV:Body
-
SOAP-ENV:Fault
SOAP-ENV:Client
[ISS.0088.9109] SOAP is only supported using HTTP POST protocol
http://10.191.23.12:5555/soap/rpc
</SOAP-ENV:Fault>
</SOAP-ENV:Body>
</SOAP-ENV:Envelope>
can any one please suggest me how to call this webservice by useing URL and where to get the url to call the webservice…
Thanks in Advance