I am a real newbie to XSLT, and probably this question is a piece of cake for you.
I have the following XML :
When I’m “positioned” in the element. How do I find out of there is any element present ?
Cheers
/Andreas
Hello Nietzer,
I don’t really get your question … Perhaps you are mistaking sibling nodes with child nodes.
Sibling nodes of a node are the “brothers” & “sisters” nodes of the node.
So, as “complexType” is a child node of the “element” node, your XSL template could be :
<xsl:template match=“element[@name = ‘ReferenceDetails’]”>
xsl:choose
<xsl:when test=“complexType”>
</xsl:when>
xsl:otherwise
</xsl:otherwise>
</xsl:choose>
</xsl:template>
Here you go.
If you have any question, feel free to ask.
Bertrand Martel
Software AG France