Use /part [023]+555-A/
where the + indicates one or more instances of characters from the set, which I assume is what you’re after. If not please advise and we can get the right expression to use.
This worked with both a branch label and with PSUtilities.regex:matches (without the surrounding /).
My test with PSUtilities.regex:matches using
part [023]555-A
and value part 02555-A resulted in no match. I’m using IS 6.1 on JVM 1.4.2.
The format of the regular expressions on this page may be slightly different than what you’d need in IS, but you can get the bulk of your regex pattern testing done here and then tweak for IS, if necessary.
reamon, what i want to is only to match the firsts tree strings not the forth one (with 0 AND 2)
mcarlson, the results retrun by the javascript version and the asp version are different.
are you agree with me that the regexp [023] or part [023]555
both must match with
part 0555
but not with
part 02555
the thing i want to test is a string that begin with a string that contains only 0 or 2 or 3. Not two of the precent characters. i have no matter of "part " and “555”. that was to take the exemple of webMethods Developer User’s Guide page 415. i want that “^0$” or “^2$” “^3$” match but not “^02$”
i don’t understand why regexp have different match on different languages implementations …
i don’t understand the difference of interpretation between part[023]555 and [023] expect of course part and 555.
Then I think the expression you started off with, part [023]555, is the one you want for the example given.
No. [023] will match when 0, 2, or 3 occurs anywhere within the string. It will, and should, match both your examples.
To make sure I understand, you’re looking for a regex way of implementing this:
BRANCH on someVar
0: SEQUENCE (do something)
2: SEQUENCE (do the same thing as 0)
3: SEQUENCE (do the same thing as 0 and 2)
$default: SEQUENCE (no match)
If I understand what you’re after, then /^0$|^2$|^3$/should do what you want.
Unless you anchor the regex with ^ or $ (beginning of string or end of string), then the pattern can occur anywhere within your string. Using your example, expression part [023]555 will match:
part 0555-A
part 2555-A
part 3555-A
junk part 3555-A fiddle faddle
garbage part 0555xxxyyyzzz
this string will not match
part 02555-A
But [023] will match all of them. Because this expression says “match if 0, 2 or 3 occur anywhere within the string.”
Seems to me that you want to ensure that the 1st character of the string is 0, 2, or 3 AND that the 2nd character of the string is NOT 0, 2, or 3. Is this correct?
If so, then assuming that your string is at least 2 characters long, you can use this regular expression: /[1][^023]/
this regex will match any strings like:
(anything_except_023)0or2or3(anything_except_023),
if You use /[023]/ only, it will match any string that have at least one 0 or 2 or 3,
but if you need to match strings that have any occurence of 0 or 2 or 3, but at lest one of them is not precede by 0 or 2 or 3, then you need to use:
/(^|[^023])023/
this will match strings like:
safa0safs0afsdf and sad02adfsd3test
but not
sassfd02sdafds
and the third option if You one to match
safa0safs0afsdf but not sad02adfsd3test
than an expression like
/^([^023](^|[^023])023[^023])*$/
should be use:)
this expression says that any occurence of 0,2,3 will not be precede by 0,2,3.
You would have to know the pattern you are receiving in advance, from a standard, by agreement with a partner or from an indicator elsewhere in the data. There’s no way to determine it from the date alone. Retrieve the pattern from wherever it is stored, translate it to a consistent format of your choosing, map it to a string variable and branch on the value of that.
You must have the patterns that you are expecting to receive and then use branch operation and translate it to expected format.simple say there is no dyanamic way…