tag remove log from XML output

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1

Hi,I need some help.

I have input XML…depend on the logic output xml will be generated.

based on condition while mapping under LOOP. We do not want some tag in output xml.

but I am getting empty tag in output. (line 3 and 4 are empty tags)

<?xml version="1.0"?> Mr. C Mexciko 10000 PM

in the documentToXMLString step I,set “generateRequiredTags=false” and give document name in ‘documentTypeName’ field.

Still empty tags are coming…

Could you please suggest how to remove those empty tag.’

Thanks,
Nabanita

2

Hi Nabanita,

can you provide an outline of your transformation logic please?

Assuming Emp is a list, where is not clear which ones and how many of the entries are empty you should do the following:

Loop over the list Emp and only map the entries if “Emp is not empty” via BRANCH.

Regards,
Holger

3

try to create a xslt service with this, it will filter empty nodes for you:

<?xml version="1.0" encoding="UTF-8"?>

<xsl:stylesheet version=“2.0” xmlns:xsl=“XSLT Namespace”>
<xsl:output method=“xml”/>
<xsl:template match=“/”>
<xsl:apply-templates select=““/>
</xsl:template>
<xsl:template match=””>
<xsl:if test=“.!=‘’”>
xsl:copy
<xsl:copy-of select=“@*”/>
xsl:apply-templates/
</xsl:copy>
</xsl:if>
</xsl:template>
</xsl:stylesheet>

4

Hi,

The document you are using to generate the output has those fields defined (even if empty) or set as null?

Are those fields set as required=true in the original document type?

I don’t know if there is a better way, but before converting to XML, you could use a BRANCH operation on that field and use a MAP operation to drop the field from the document if it’s empty (leave the label empty) or if it’s null (another operation whose label is set to $null).

Best Regards,

5

Many thanks