Compare two sets of arrays

[Yaniv_Zisano]

I want to compare 2 sets of array of 16 items to determine if the items are identical both in position and values.

wrong:
arr1 (1,2,3,4,4,6,7,8,9,10,11,12,13,14,15,16)
arr2 (1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16)

wrong:
arr1 (2,1,3,4,5,6,7,8,9,10,11,12,13,14,15,16)
arr2 (1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16)

correct:
arr1 (1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16)
arr2 (1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16)

How can I achieve this?

[Lukas_Hundemer]

if arr1(1:16) = arr2(1:16)
Print ‘same’
else
Print ‘not same’
end-if

Do not use “(*)” on both sides.

Kind regards
Lukas

[amnon_a]

You can redefine both arrays and compare the redefined fields

[Avik_Dey1 (Avik Dey)]

Hi, you can use the equals() method of java.util.Arrays.

[Steve_Robinson]

If you are concerned with performance, redefine the two arrays as follows (I am simply assuming the arrays are alpha and five positions long).

1 arr1 (a5,1:16) would become #all1 (a80)

A similar change would be made for arr2 and #all2.

Now you check to see if #all1 = #all2.

One comparison as opposed to sixteen.

If this is done a few million times a day, you might not have to increase the power of your computer.

Steve Robinson
(still concerned about performance)

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